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Driver Finder 2.1.0.0 Setup Serial Key.47Click Here > =2sKjjPNVIDIA-GeForce-8550-GPGPU-Series-Graphics-Cards-for-PCs.Q:Does this function really have a unique root?I am doing some research on a function $g(x)=x^3+x+1$, and while I was thinking about the function in general, I wondered about the uniqueness of a root of this function. I tried to visualize it on the $x$-axis, and it seems that for each $x$, there is only one root. However, WolframAlpha tells me that the third root of $x^3+x+1$ is $x=\frac4+\sqrt212$. So the other two roots are negative. However, if I say that I proved that the third root is $x=\frac4+\sqrt212$ and therefore $x$ is the only root, my classmate will tell me that I have proved the existence of another root.Now I know this might be true but, is there a way to prove that $x=\frac4+\sqrt212$ is the only root in a rigorous manner?A:The problem of a cubic polynomial is that the graph of a function is symmetric with respect to the line of $x = y$ about the $y$-axis.For a cubic function, we have roots at $\pm 1$ and $\pm 1/3$ (on the imaginary axis) and the two "principal roots" $\pm \sqrt27/14$.But the third root is on the imaginary axis, which means that the point $x = 0$ is a local (analytical) minimum of the function, which is not necessarily true for a polynomial.A:You can prove that there is only one positive root (and therefore only one negative root) by studying the behaviour of the function as $x \rightarrow 0$.What you have to do is write the function in the form $ax^3 + bx^2 + cx + d$, which can be done easily as the function satisfies the three-term recurrence relationx \left( x + 1 \right) \left( x - \frac14 \right) ee730c9e81

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